Chapter 2

Problem #3

  1. How many bits are there on a 600 MB CD?

    2. 600 * 1,048,576 = 629,145,600

    629,145,600 * 8 = 5,033,164,800 bits or

    The answer is 5,033,164,800 bits

  2. How many volumes can be put on one CD?
    3.

    DATA:

    Message space 6 * 9 = 54 lines for the page at single space

    6.5 *10 = 65

    8 bits

    1000 pages

    IMAGES

    100 images

    SGV resolution (1024 * 768 * 8)

    AUDIO

    30 minutes

    60 sec p/ minute

    16,000 samples/sec

    6 bits p/sample

     

    Information Types

    Operation

    Totals

    Data

    1000 * 54 * 65 * 8

    = 28.1 Mbits

    Images

    100 * (1024 * 768 * 8)

    = 629.1 Mbits

    Audio

    1800 * 16,000 * 6

    = 172.8 Mbits

    TOTAL

    		  

    830 Mb p/ volume

     

    Answer: By dividing the capacity of the CD by the size of a volume

    ( 5000 / 830 ) we get approximately 6 volumes on one CD

  3. How long will it take to transmit a volume over a T-1 facility?

    4. Answer : 830 Mb / 1.544 Mbps = 537.6 sec or approximately 9 minutes

  4. If compressed at 3:1 for text, 10:1 for pictures, and 2:1 for audio, how many volumes will fit on a CD? How long will it take to transmit over a T-1?

Information Types

Compression

Operation

Totals

Data

3:1

28.1 / 3

= 9.4 Mbits

Images

10:1

629.1 / 10

= 62.9 Mbits

Audio

2:1

172.8 / 2

= 86.4 Mbits

TOTAL

    

158.7 Mb p/ volume

Answer: By dividing the capacity of the CD by the size of a volume

( 5000 / 158.7 ) we get approximately 32 volumes on one CD

Answer : 158.7 Mb / 1.544 Mbps = approximately 103 sec or 1 minute and 43 seconds